- angle between ramp and ground is 30*
- top of ramp is 1.1m above the ground
- the riders speed at the top of the ramp is 10 m/s
- vertical velocity is 5 m/s
Calculate the maximum height that the rider will reach above the ground
Can you help me solve this please as I’ve forgotten how to do this
Is there an image to go with the question? I feel like there could be important information I’m missing. For example, I’m not sure if the rider is starting at the top of the ramp, and riding down towards a second ramp, or riding up and off a ramp.
If the rider is riding up, and off, the ramp:
Assuming their vertical velocity on leaving the ramp is 5m/s, you know their initial vertical velocity (vi=5m/s).
At the top of their trajectory (the path they follow as a projectile), their velocity would be zero (vf=0m/s). So this is the riders final velocity at maximum height.
You know accceleration due to gravity is -9.8 m/s^-2 (a=-9.8 m/s^-2 the negative value will be important in your calculation)
You are trying to find vertical displacement, d
You should have a kinematic equation that involves those four terms. Rearrange for to find d.
Remember to add your answer to the height of the ramp, as the question asks for the height above the ground.
Does that make sense in the context of the question?
@doug.walker here is the image that goes with it
Great, in that case my suggestion was correct. Did you manage to follow along and find the solution?
yes, thank you so much for your help